In this issue of Math in the News we look at applications of math from the Sochi Olympics. Specficially we look at ski jumping and develop a quadratic model based on given data.
2. #Sochi2014
Math abounds in the Olympics, whether it’s
data around Olympic records, medals won, or
other statistics. In this issue we will look at the
dramatic sport of ski jumping, and its
application to quadratics and other non-linear
models. Take a look at this interactive to learn
more about ski jumping (Source: NY Times).
http://www.nytimes.com/newsgraphics/2014/so
chi-olympics/ski-jumping.html
3. #Sochi2014
The path of the ski
jumper can be
approximated with a
parabola. From the
NY Times interactive
we learn that the skier
starts her jump 15 ft
off the ground and
can cover the length
of a football field. We
can sketch out a
model for this.
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We get three
points: (0, 15), the
starting point,
(h, k), the vertex of
the parabola, and
(x, y) where the
skier lands. The
slant distance
covered is 300 ft.
and is the
hypotenuse of a
right triangle.
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We now have two coordinates and can
conceive of the vertex of the parabola, (h, k).
From the video we see that the skier elevates
by about 3 ft. We can then assign a value to k.
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The equation for a parabola in vertex form has
two variables, a and k, that are unknown. But
we do have two coordinates and can solve for
these two values.
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Here is the solution using the first set of
coordinates. We end up with an equation that
shows a as a function of k.
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Here is the solution using the second set of
coordinates. We end up with a second equation
that shows a as a function of k.
14. #Sochi2014
Now that you’ve seen how to construct a
quadratic model using curve-fitting techniques,
expand on your work:
• Try different values for k to see what impact
it has on how far the ski jumper jumps.
• Try a longer slant height to see what the
equation is for different values of k.