SlideShare une entreprise Scribd logo
1  sur  2
Télécharger pour lire hors ligne
typed by Sean Bird, Covenant Christian High School
                updated August 15, 2009
                                                                    AP CALCULUS
                                                              Stuff you MUST know Cold                                               * means topic only on BC
    Curve sketching and analysis                                  Differentiation Rules                               Approx. Methods for Integration
 y = f(x) must be continuous at each:                       Chain Rule                                              Trapezoidal Rule
                dy                                           d                      du    dy dy du                      b
critical point:    = 0 or undefined
                dx and look out for endpoints                dx
                                                                [ f (u )] = f '(u ) dx OR dx = du dx                ∫a
                                                                                                                            f ( x)dx =           1 b− a
                                                                                                                                                 2 n      [ f ( x0 ) + 2 f ( x1 ) + ...
local minimum:                                                                                                                                                                + 2 f ( xn −1 ) + f ( xn )]
 dy goes (–,0,+) or (–,und,+) or d 2 y >0                   Product Rule                                            Simpson’s Rule
 dx                              dx 2                                                                                   b

local maximum:
                                                              d
                                                              dx
                                                                 (uv) =
                                                                        du
                                                                        dx
                                                                           v+u
                                                                               dv
                                                                               dx
                                                                                  OR u ' v + uv '                   ∫a
                                                                                                                            f ( x)dx =
                                                      2                                                                     1
  dy goes (+,0,–) or (+,und,–) or d y <0                                                                                    3   ∆x[ f ( x0 ) + 4 f ( x1 ) + 2 f ( x2 ) + ...
  dx                              dx 2                                                                                                        2 f ( xn −2 ) + 4 f ( xn−1 ) + f ( xn )]
point of inflection: concavity changes
                                                            Quotient Rule
 d 2 y goes from (+,0,–), (–,0,+),
                                                               d u           du
                                                                               dx   v −u   dv
                                                                                           dx        u ' v − uv '
                                                                   =
                                                               dx  v               v2
                                                                                                OR
                                                                                                          v2
 dx 2          (+,und,–), or (–,und,+)                                                                                           Theorem of the Mean Value
                                                                                                                                  i.e. AVERAGE VALUE
                                                                                                                    If the function f(x) is continuous on [a, b]
              Basic Derivatives
                                                          “PLUS A CONSTANT”                                         and the first derivative exists on the
                  d n                                                                                               interval (a, b), then there exists a number
                  dx
                           ( )
                        x = nx n−1                            The Fundamental Theorem of                            x = c on (a, b) such that
                                                                       Calculus                                                                                          b
                d
                    ( sin x ) = cos x                                                                                                                f (c ) =
                                                                                                                                                              ∫          a
                                                                                                                                                                             f ( x)dx
               dx                                                       b
                                                                                                                                            (b − a)
              d
                   ( cos x ) = − sin x
                                                                    ∫a
                                                                            f ( x)dx = F (b) − F (a)
                                                                                                                    This value f(c) is the “average value” of
              dx                                                            where F '( x) = f ( x)                  the function on the interval [a, b].
               d
                   ( tan x ) = sec2 x
              dx
                                                                         Corollary to FTC                              Solids of Revolution and friends
              d
                  ( cot x ) = − csc2 x                                                                              Disk Method
             dx                                                d b( x)                                                                  x =b
                                                                                                                         V =π∫
                                                                                                                                                               2
                                                                                                                                               [ R ( x)]
                                                               dx ∫a ( x )
            d                                                              f (t )dt =                                                                              dx
                ( sec x ) = sec x tan x                                                                                                 x=a

            dx                                                                                                      Washer Method
           d                                                       f (b( x))b '( x) − f (a ( x))a '( x)
           dx
              ( csc x ) = − csc x cot x                                                                                  V =π∫
                                                                                                                                        b

                                                                                                                                        a
                                                                                                                                            ([ R( x)] − [r ( x)] ) dx
                                                                                                                                                             2                     2


                                                              Intermediate Value Theorem                            General volume equation (not rotated)
                 d              1 du
                     ( ln u ) =                           If the function f(x) is continuous on [a, b],                             b
                dx              u dx                      and y is a number between f(a) and f(b),                       V = ∫ Area ( x) dx
                                                                                                                                    a
                  d u            du                       then there exists at least one number x= c
                 dx
                           ( )
                        e = eu
                                  dx                      in the open interval (a, b) such that                     *Arc Length L = ∫ 1 + [ f '( x)] dx
                                                                                                                                                                   b                       2

                                                                                                                                                                 a
          where u is a function of x,                                        f (c ) = y .                                                                            b
                                                                                                                                                          =∫
                                                                                                                                                                                       2           2
             and a is a constant.                                                                                                                                  a
                                                                                                                                                                             [ x '(t )] + [ y '(t )]   dt
              More Derivatives                                                                                      Distance, Velocity, and Acceleration
         d  −1 u                         1     du                Mean Value Theorem                               velocity = d (position)
              sin    =
         dx 
                 a
                                         2
                                         a −u  2 dx                                                                                              dt
                                                          If the function f(x) is continuous on [a, b],                                                   d (velocity)
            d                               −1                                                                      acceleration =
                                                          AND the first derivative exists on the
            dx
                   (
                cos −1 x =       )                        interval (a, b), then there is at least one
                                                                                                                                                          dt
                              1 − x2                                                                                                                                   dx dy
                                                          number x = c in (a, b) such that                          *velocity vector =                                   ,
         d  −1 u            a       du                                                                                                                               dt dt
              tan        =          ⋅                                           f (b) − f (a )
        dx         a  a 2 + u 2 dx
                                                                      f '(c) =                .
                                                                                                                    speed = v = ( x ')2 + ( y ') 2 *
                                                                                    b−a
              d                −1
             dx
                       (
                  cot −1 x =
                             1 + x2
                                     )                                                                              displacement =                      ∫t
                                                                                                                                                          tf
                                                                                                                                                                 v dt
                                                                                                                                                          o

      d  −1 u               a          du                                 Rolle’s Theorem                                                      final time

      dx 
         
           sec        =
                  a  u u 2 − a 2 dx
                    
                                       ⋅                                                                            distance =              ∫initial time v dt
                                                          If the function f(x) is continuous on [a, b],                                        tf
           d
               (
              csc −1 x =
                           −1
                             )                            AND the first derivative exists on the                                            ∫t   o
                                                                                                                                                       ( x ') 2 + ( y ') 2 dt *
           dx            x x2 − 1                         interval (a, b), AND f(a) = f(b), then there              average velocity =
                                                          is at least one number x = c in (a, b) such                         final position − initial position
           d u( x)                     du
           dx
               ( )
               a      = a ( ) ln a ⋅
                            u x

                                       dx
                                                          that
                                                                             f '(c) = 0 .
                                                                                                                            =
                                                                                                                                          total time
                                                                                                                               ∆x
              d                    1                                                                                        =
                 ( log a x ) =                                                                                                 ∆t
              dx                x ln a
BC TOPICS and important TRIG identities and values
              l’Hôpital’s Rule                           Slope of a Parametric equation                                     Values of Trigonometric
        f (a) 0            ∞                        Given a x(t) and a y(t) the slope is                                  Functions for Common Angles
   If          = or = ,
        g (b) 0            ∞                                           dy dy
                                                                           = dt                                           θ        sin θ      cos θ      tan θ
            f ( x)         f '( x)                                     dx dx
then lim           = lim                                                      dt
      x →a g ( x)    x → a g '( x )                                                                                       0°         0          1          0
             Euler’s Method                                                  Polar Curve                                   π         1           3          3
If given that dy = f ( x, y ) and that              For a polar curve r(θ), the                                            6         2          2          3
                dx
                                                    AREA inside a “leaf” is
the solution passes through (xo, yo),                                        θ2               2
                                                                                                                           π          2          2
 y ( xo ) = yo                                                             ∫θ1
                                                                                  1
                                                                                  2
                                                                                       r (θ )  dθ
                                                                                                                         4         2          2
                                                                                                                                                           1

                                                    where θ1 and θ2 are the “first” two times that r =                     π          3         1
                                                    0.                                                                                                      3
 y ( xn ) = y ( xn−1 ) + f ( xn−1 , yn−1 ) ⋅ ∆x                                                                            3         2          2
                                                    The SLOPE of r(θ) at a given θ is
In other words:                                                          dy dy / dθ                                        π
                                                                           =                                                         1          0        “∞ ”
                xnew = xold + ∆x                                         dx dx / dθ                                        2
                          dy                                                                                               π         0         −1          0
                                                                              dθ  r (θ ) sin θ 
                                                                               d
                                                                           = d                 
       ynew = yold +                         ⋅ ∆x                                                                     Know both the inverse trig and the trig
                          dx ( xold , yold )
                                                                              dθ  r (θ ) cos θ 
                                                                                                                    values. E.g. tan(π/4)=1 & tan-1(1)= π/4
          Integration by Parts                                               Ratio Test                                           Trig Identities
                                                                   ∞
                                                                                                                      Double Argument
             ∫   udv = uv − ∫ vdu                   The series ∑ ak converges if
                                                                  k =0
                                                                                                                      sin 2 x = 2sin x cos x
Integral of Log                                                                                                       cos 2 x = cos 2 x − sin 2 x = 1 − 2sin 2 x
Use IBP and let u = ln x (Recall                                                        ak +1
                                                                                 lim          <1                                1
u=LIPET)                                                                         k →∞    ak                           cos 2 x = (1 + cos 2 x )
                                                                                                                                2
         ∫   ln x dx = x ln x − x + C               If the limit equal 1, you know nothing.

               Taylor Series                                                                                                    1
If the function f is “smooth” at x =                             Lagrange Error Bound                                 sin 2 x =    (1 − cos 2 x )
                                                                                                                                 2
a, then it can be approximated by                   If Pn ( x) is the nth degree Taylor polynomial                    Pythagorean
the nth degree polynomial
                                                    of f(x) about c and f ( n+1) (t ) ≤ M for all t                   sin 2 x + cos 2 x = 1
  f ( x) ≈ f (a ) + f '(a )( x − a)                                                                                   (others are easily derivable by
                                                    between x and c, then
                   +
                       f ''(a)
                                 ( x − a)2 + …                                                                        dividing by sin2x or cos2x)
                                                                                             M          n+1
                         2!                                  f ( x) − Pn ( x) ≤                     x−c               1 + tan 2 x = sec 2 x
                       f ( n ) (a)
                                                                                          ( n + 1)!
                   +               ( x − a)n .                                                                        cot 2 x + 1 = csc 2 x
                           n!                                                                                         Reciprocal
             Maclaurin Series                                                                                                     1
A Taylor Series about x = 0 is                            Alternating Series Error Bound                              sec x =         or cos x sec x = 1
                                                                                                                               cos x
called Maclaurin.
                                                                                                                                 1
                        x 2 x3                                N                                                       csc x =         or sin x csc x = 1
                                                    If S N = ∑ ( −1) an is the Nth partial sum of a
                                                                            n
         ex = 1 + x + + +…                                                                                                     sin x
                        2! 3!                                k =1                                                     Odd-Even
                     2
                   x       x4                       convergent alternating series, then                               sin(–x) = – sin x (odd)
      cos x = 1 − + − …
                   2! 4!                                           S∞ − S N ≤ aN +1                                   cos(–x) = cos x        (even)
                    x3 x5                                                                                             Some more handy INTEGRALS:
       sin x = x − + − …

         1
                    3! 5!                                                 Geometric Series
                                                                                                           ∞          ∫   tan x dx = ln sec x + C
             = 1 + x + x2 + x3 + …                  a + ar + ar 2 + ar 3 + … + ar n −1 + … = ∑ ar n −1                             = − ln cos x + C
      1− x                                                                                                n =1

                    x 2 x3 x 4                                                                         a
 ln( x + 1) = x − + − + …
                     2         3 4
                                                    diverges if |r|≥1; converges to
                                                                                                      1− r
                                                                                                           if |r|<1   ∫   sec x dx = ln sec x + tan x + C

This is available at http://covenantchristian.org/bird/Smart/Calc1/StuffMUSTknowColdNew.htm

Contenu connexe

Tendances

Ts cours derivation_formulaire 6
Ts cours derivation_formulaire 6Ts cours derivation_formulaire 6
Ts cours derivation_formulaire 6
Mohamedlemine Sarr
 
3.3 graphs of factorable polynomials and rational functions
3.3 graphs of factorable polynomials and rational functions3.3 graphs of factorable polynomials and rational functions
3.3 graphs of factorable polynomials and rational functions
math265
 
1.1 review on algebra 1
1.1 review on algebra 11.1 review on algebra 1
1.1 review on algebra 1
math265
 
4.1 derivatives as rates linear motions
4.1 derivatives as rates linear motions4.1 derivatives as rates linear motions
4.1 derivatives as rates linear motions
math265
 
2.6 more computations of derivatives
2.6 more computations of derivatives2.6 more computations of derivatives
2.6 more computations of derivatives
math265
 
4.2 more derivatives as rates
4.2 more derivatives as rates4.2 more derivatives as rates
4.2 more derivatives as rates
math265
 
1.4 review on log exp-functions
1.4 review on log exp-functions1.4 review on log exp-functions
1.4 review on log exp-functions
math265
 
1.3 review on trig functions
1.3 review on trig functions1.3 review on trig functions
1.3 review on trig functions
math265
 
5.2 the substitution methods
5.2 the substitution methods5.2 the substitution methods
5.2 the substitution methods
math265
 
3.4 derivative and graphs
3.4 derivative and graphs3.4 derivative and graphs
3.4 derivative and graphs
math265
 

Tendances (20)

Ts cours derivation_formulaire 6
Ts cours derivation_formulaire 6Ts cours derivation_formulaire 6
Ts cours derivation_formulaire 6
 
3.3 graphs of factorable polynomials and rational functions
3.3 graphs of factorable polynomials and rational functions3.3 graphs of factorable polynomials and rational functions
3.3 graphs of factorable polynomials and rational functions
 
2 integration and the substitution methods x
2 integration and the substitution methods x2 integration and the substitution methods x
2 integration and the substitution methods x
 
1.1 review on algebra 1
1.1 review on algebra 11.1 review on algebra 1
1.1 review on algebra 1
 
4.1 derivatives as rates linear motions
4.1 derivatives as rates linear motions4.1 derivatives as rates linear motions
4.1 derivatives as rates linear motions
 
Derivatives and their Applications
Derivatives and their ApplicationsDerivatives and their Applications
Derivatives and their Applications
 
2.6 more computations of derivatives
2.6 more computations of derivatives2.6 more computations of derivatives
2.6 more computations of derivatives
 
Lesson 10: The Chain Rule
Lesson 10: The Chain RuleLesson 10: The Chain Rule
Lesson 10: The Chain Rule
 
4.2 more derivatives as rates
4.2 more derivatives as rates4.2 more derivatives as rates
4.2 more derivatives as rates
 
1.4 review on log exp-functions
1.4 review on log exp-functions1.4 review on log exp-functions
1.4 review on log exp-functions
 
Lesson 19: Maximum and Minimum Values
Lesson 19: Maximum and Minimum ValuesLesson 19: Maximum and Minimum Values
Lesson 19: Maximum and Minimum Values
 
Lesson 26: Integration by Substitution (slides)
Lesson 26: Integration by Substitution (slides)Lesson 26: Integration by Substitution (slides)
Lesson 26: Integration by Substitution (slides)
 
Lecture 10(asymptotes)
Lecture 10(asymptotes)Lecture 10(asymptotes)
Lecture 10(asymptotes)
 
Lesson 9: The Product and Quotient Rule
Lesson 9: The Product and Quotient RuleLesson 9: The Product and Quotient Rule
Lesson 9: The Product and Quotient Rule
 
1.0 factoring trinomials the ac method and making lists-x
1.0 factoring trinomials  the ac method and making lists-x1.0 factoring trinomials  the ac method and making lists-x
1.0 factoring trinomials the ac method and making lists-x
 
1.3 review on trig functions
1.3 review on trig functions1.3 review on trig functions
1.3 review on trig functions
 
Lesson 8: Derivatives of Polynomials and Exponential functions
Lesson 8: Derivatives of Polynomials and Exponential functionsLesson 8: Derivatives of Polynomials and Exponential functions
Lesson 8: Derivatives of Polynomials and Exponential functions
 
Lesson 14: Exponential Functions
Lesson 14: Exponential FunctionsLesson 14: Exponential Functions
Lesson 14: Exponential Functions
 
5.2 the substitution methods
5.2 the substitution methods5.2 the substitution methods
5.2 the substitution methods
 
3.4 derivative and graphs
3.4 derivative and graphs3.4 derivative and graphs
3.4 derivative and graphs
 

En vedette

Calculus Cheat Sheet All
Calculus Cheat Sheet AllCalculus Cheat Sheet All
Calculus Cheat Sheet All
Moe Han
 
Trigo Sheet Cheat :D
Trigo Sheet Cheat :DTrigo Sheet Cheat :D
Trigo Sheet Cheat :D
Quimm Lee
 
Ap calculus bc integration multiple choice practice solutions
Ap calculus bc integration multiple choice practice solutionsAp calculus bc integration multiple choice practice solutions
Ap calculus bc integration multiple choice practice solutions
jaflint718
 
Distance and Midpoint Formulas.pdf
Distance and Midpoint Formulas.pdfDistance and Midpoint Formulas.pdf
Distance and Midpoint Formulas.pdf
bwlomas
 
Formulas geometry
Formulas geometryFormulas geometry
Formulas geometry
msnancy
 
Distance and Midpoint Formulas Concepts.pdf
Distance and Midpoint Formulas Concepts.pdfDistance and Midpoint Formulas Concepts.pdf
Distance and Midpoint Formulas Concepts.pdf
LomasGeoC
 
ForMuLas FoR GeoMeTry
ForMuLas FoR GeoMeTryForMuLas FoR GeoMeTry
ForMuLas FoR GeoMeTry
Akane Moon
 
Maths coordinate geometry formulas.
Maths   coordinate geometry formulas.Maths   coordinate geometry formulas.
Maths coordinate geometry formulas.
tahmiinaaoxo
 

En vedette (19)

Calculus Cheat Sheet All
Calculus Cheat Sheet AllCalculus Cheat Sheet All
Calculus Cheat Sheet All
 
Trig cheat sheet
Trig cheat sheetTrig cheat sheet
Trig cheat sheet
 
Basics of calculus
Basics of calculusBasics of calculus
Basics of calculus
 
Calculus II - 1
Calculus II - 1Calculus II - 1
Calculus II - 1
 
Calculus
CalculusCalculus
Calculus
 
Trigo Sheet Cheat :D
Trigo Sheet Cheat :DTrigo Sheet Cheat :D
Trigo Sheet Cheat :D
 
Fractional calculus and applications
Fractional calculus and applicationsFractional calculus and applications
Fractional calculus and applications
 
Trigonometry cheat sheet
Trigonometry cheat sheetTrigonometry cheat sheet
Trigonometry cheat sheet
 
Ap calculus bc integration multiple choice practice solutions
Ap calculus bc integration multiple choice practice solutionsAp calculus bc integration multiple choice practice solutions
Ap calculus bc integration multiple choice practice solutions
 
Tips And Tricks For The Ap Calculus Exam
Tips And Tricks For The Ap Calculus ExamTips And Tricks For The Ap Calculus Exam
Tips And Tricks For The Ap Calculus Exam
 
Distance and Midpoint Formulas.pdf
Distance and Midpoint Formulas.pdfDistance and Midpoint Formulas.pdf
Distance and Midpoint Formulas.pdf
 
Formulas geometry
Formulas geometryFormulas geometry
Formulas geometry
 
Distance and Midpoint Formulas Concepts.pdf
Distance and Midpoint Formulas Concepts.pdfDistance and Midpoint Formulas Concepts.pdf
Distance and Midpoint Formulas Concepts.pdf
 
ForMuLas FoR GeoMeTry
ForMuLas FoR GeoMeTryForMuLas FoR GeoMeTry
ForMuLas FoR GeoMeTry
 
GREKing: PPT offers
GREKing: PPT offersGREKing: PPT offers
GREKing: PPT offers
 
128198243 makalah-probabilitas
128198243 makalah-probabilitas128198243 makalah-probabilitas
128198243 makalah-probabilitas
 
GREKing: The most repeated type of quants problem.
GREKing: The most repeated type of quants problem.GREKing: The most repeated type of quants problem.
GREKing: The most repeated type of quants problem.
 
GREKing: Vedic Maths Concept
GREKing: Vedic Maths ConceptGREKing: Vedic Maths Concept
GREKing: Vedic Maths Concept
 
Maths coordinate geometry formulas.
Maths   coordinate geometry formulas.Maths   coordinate geometry formulas.
Maths coordinate geometry formulas.
 

Similaire à Stuff You Must Know Cold for the AP Calculus BC Exam!

Emat 213 study guide
Emat 213 study guideEmat 213 study guide
Emat 213 study guide
akabaka12
 
Differential Equation Tutorial 1
Differential Equation Tutorial 1Differential Equation Tutorial 1
Differential Equation Tutorial 1
Yong Sheng
 
Introduction to inverse problems
Introduction to inverse problemsIntroduction to inverse problems
Introduction to inverse problems
Delta Pi Systems
 
Stationary Points Handout
Stationary Points HandoutStationary Points Handout
Stationary Points Handout
coburgmaths
 

Similaire à Stuff You Must Know Cold for the AP Calculus BC Exam! (20)

Common derivatives integrals_reduced
Common derivatives integrals_reducedCommon derivatives integrals_reduced
Common derivatives integrals_reduced
 
Emat 213 study guide
Emat 213 study guideEmat 213 study guide
Emat 213 study guide
 
Regras diferenciacao
Regras diferenciacaoRegras diferenciacao
Regras diferenciacao
 
01 regras diferenciacao
01   regras diferenciacao01   regras diferenciacao
01 regras diferenciacao
 
Beam theory
Beam theoryBeam theory
Beam theory
 
Double integration
Double integrationDouble integration
Double integration
 
Chapter 15
Chapter 15Chapter 15
Chapter 15
 
Lect3cg2011
Lect3cg2011Lect3cg2011
Lect3cg2011
 
Calculus Final Exam
Calculus Final ExamCalculus Final Exam
Calculus Final Exam
 
Differential Equation Tutorial 1
Differential Equation Tutorial 1Differential Equation Tutorial 1
Differential Equation Tutorial 1
 
Cea0001 ppt project
Cea0001 ppt projectCea0001 ppt project
Cea0001 ppt project
 
Lesson 27: Evaluating Definite Integrals
Lesson 27: Evaluating Definite IntegralsLesson 27: Evaluating Definite Integrals
Lesson 27: Evaluating Definite Integrals
 
Ism et chapter_6
Ism et chapter_6Ism et chapter_6
Ism et chapter_6
 
Ism et chapter_6
Ism et chapter_6Ism et chapter_6
Ism et chapter_6
 
Chapter 4(differentiation)
Chapter 4(differentiation)Chapter 4(differentiation)
Chapter 4(differentiation)
 
Lesson 27: Evaluating Definite Integrals
Lesson 27: Evaluating Definite IntegralsLesson 27: Evaluating Definite Integrals
Lesson 27: Evaluating Definite Integrals
 
Lista de derivadas e integrais
Lista de derivadas e integraisLista de derivadas e integrais
Lista de derivadas e integrais
 
Introduction to inverse problems
Introduction to inverse problemsIntroduction to inverse problems
Introduction to inverse problems
 
Sect1 6
Sect1 6Sect1 6
Sect1 6
 
Stationary Points Handout
Stationary Points HandoutStationary Points Handout
Stationary Points Handout
 

Plus de A Jorge Garcia

Plus de A Jorge Garcia (20)

LIMACON 2023 Brochure
LIMACON 2023 BrochureLIMACON 2023 Brochure
LIMACON 2023 Brochure
 
2022-RESUME-NEW
2022-RESUME-NEW2022-RESUME-NEW
2022-RESUME-NEW
 
MAT122 DAY508 MEETING 44 of 45 2021.1217 FRIDAY
MAT122 DAY508 MEETING 44 of 45 2021.1217 FRIDAYMAT122 DAY508 MEETING 44 of 45 2021.1217 FRIDAY
MAT122 DAY508 MEETING 44 of 45 2021.1217 FRIDAY
 
MAT122 DAY507 MEETING 43 of 45 2021.1216 THURSDAY
MAT122 DAY507 MEETING 43 of 45 2021.1216 THURSDAYMAT122 DAY507 MEETING 43 of 45 2021.1216 THURSDAY
MAT122 DAY507 MEETING 43 of 45 2021.1216 THURSDAY
 
MAT122 DAY506 MEETING 42 of 45 2021.1215 WEDNESDAY
MAT122 DAY506 MEETING 42 of 45 2021.1215 WEDNESDAYMAT122 DAY506 MEETING 42 of 45 2021.1215 WEDNESDAY
MAT122 DAY506 MEETING 42 of 45 2021.1215 WEDNESDAY
 
MAT122 DAY308 Lesson 26 of 45
MAT122 DAY308 Lesson 26 of 45MAT122 DAY308 Lesson 26 of 45
MAT122 DAY308 Lesson 26 of 45
 
MAT122 DAY307 Lesson 25 of 45
MAT122 DAY307 Lesson 25 of 45MAT122 DAY307 Lesson 25 of 45
MAT122 DAY307 Lesson 25 of 45
 
MAT122 DAY306 Lesson 24 of 45
MAT122 DAY306 Lesson 24 of 45MAT122 DAY306 Lesson 24 of 45
MAT122 DAY306 Lesson 24 of 45
 
MAT122 DAY305 Lesson 23 of 45
MAT122 DAY305 Lesson 23 of 45MAT122 DAY305 Lesson 23 of 45
MAT122 DAY305 Lesson 23 of 45
 
MAT122 DAY304 Lesson 22 of 45
MAT122 DAY304 Lesson 22 of 45MAT122 DAY304 Lesson 22 of 45
MAT122 DAY304 Lesson 22 of 45
 
MAT122 DAY303 Lesson 21 of 45
MAT122 DAY303 Lesson 21 of 45MAT122 DAY303 Lesson 21 of 45
MAT122 DAY303 Lesson 21 of 45
 
MAT122 DAY302 Lesson 20 of 45
MAT122 DAY302 Lesson 20 of 45MAT122 DAY302 Lesson 20 of 45
MAT122 DAY302 Lesson 20 of 45
 
MAT122 DAY301 Lesson 19 of 45
MAT122 DAY301 Lesson 19 of 45MAT122 DAY301 Lesson 19 of 45
MAT122 DAY301 Lesson 19 of 45
 
MAT122 DAY205
MAT122 DAY205MAT122 DAY205
MAT122 DAY205
 
MAT122 DAY204
MAT122 DAY204MAT122 DAY204
MAT122 DAY204
 
MAT122 DAY203
MAT122 DAY203MAT122 DAY203
MAT122 DAY203
 
MAT122 DAY202
MAT122 DAY202MAT122 DAY202
MAT122 DAY202
 
MAT122 DAY201
MAT122 DAY201MAT122 DAY201
MAT122 DAY201
 
MAT122 DAY06
MAT122 DAY06MAT122 DAY06
MAT122 DAY06
 
MAT122 DAY05
MAT122 DAY05MAT122 DAY05
MAT122 DAY05
 

Dernier

Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in DelhiRussian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
kauryashika82
 
Jual Obat Aborsi Hongkong ( Asli No.1 ) 085657271886 Obat Penggugur Kandungan...
Jual Obat Aborsi Hongkong ( Asli No.1 ) 085657271886 Obat Penggugur Kandungan...Jual Obat Aborsi Hongkong ( Asli No.1 ) 085657271886 Obat Penggugur Kandungan...
Jual Obat Aborsi Hongkong ( Asli No.1 ) 085657271886 Obat Penggugur Kandungan...
ZurliaSoop
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdf
QucHHunhnh
 

Dernier (20)

Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
Explore beautiful and ugly buildings. Mathematics helps us create beautiful d...
 
Understanding Accommodations and Modifications
Understanding  Accommodations and ModificationsUnderstanding  Accommodations and Modifications
Understanding Accommodations and Modifications
 
Micro-Scholarship, What it is, How can it help me.pdf
Micro-Scholarship, What it is, How can it help me.pdfMicro-Scholarship, What it is, How can it help me.pdf
Micro-Scholarship, What it is, How can it help me.pdf
 
PROCESS RECORDING FORMAT.docx
PROCESS      RECORDING        FORMAT.docxPROCESS      RECORDING        FORMAT.docx
PROCESS RECORDING FORMAT.docx
 
Magic bus Group work1and 2 (Team 3).pptx
Magic bus Group work1and 2 (Team 3).pptxMagic bus Group work1and 2 (Team 3).pptx
Magic bus Group work1and 2 (Team 3).pptx
 
Grant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy ConsultingGrant Readiness 101 TechSoup and Remy Consulting
Grant Readiness 101 TechSoup and Remy Consulting
 
ICT Role in 21st Century Education & its Challenges.pptx
ICT Role in 21st Century Education & its Challenges.pptxICT Role in 21st Century Education & its Challenges.pptx
ICT Role in 21st Century Education & its Challenges.pptx
 
General Principles of Intellectual Property: Concepts of Intellectual Proper...
General Principles of Intellectual Property: Concepts of Intellectual  Proper...General Principles of Intellectual Property: Concepts of Intellectual  Proper...
General Principles of Intellectual Property: Concepts of Intellectual Proper...
 
ComPTIA Overview | Comptia Security+ Book SY0-701
ComPTIA Overview | Comptia Security+ Book SY0-701ComPTIA Overview | Comptia Security+ Book SY0-701
ComPTIA Overview | Comptia Security+ Book SY0-701
 
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in DelhiRussian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
Russian Escort Service in Delhi 11k Hotel Foreigner Russian Call Girls in Delhi
 
Jual Obat Aborsi Hongkong ( Asli No.1 ) 085657271886 Obat Penggugur Kandungan...
Jual Obat Aborsi Hongkong ( Asli No.1 ) 085657271886 Obat Penggugur Kandungan...Jual Obat Aborsi Hongkong ( Asli No.1 ) 085657271886 Obat Penggugur Kandungan...
Jual Obat Aborsi Hongkong ( Asli No.1 ) 085657271886 Obat Penggugur Kandungan...
 
On National Teacher Day, meet the 2024-25 Kenan Fellows
On National Teacher Day, meet the 2024-25 Kenan FellowsOn National Teacher Day, meet the 2024-25 Kenan Fellows
On National Teacher Day, meet the 2024-25 Kenan Fellows
 
Making communications land - Are they received and understood as intended? we...
Making communications land - Are they received and understood as intended? we...Making communications land - Are they received and understood as intended? we...
Making communications land - Are they received and understood as intended? we...
 
Food safety_Challenges food safety laboratories_.pdf
Food safety_Challenges food safety laboratories_.pdfFood safety_Challenges food safety laboratories_.pdf
Food safety_Challenges food safety laboratories_.pdf
 
How to Give a Domain for a Field in Odoo 17
How to Give a Domain for a Field in Odoo 17How to Give a Domain for a Field in Odoo 17
How to Give a Domain for a Field in Odoo 17
 
Unit-IV- Pharma. Marketing Channels.pptx
Unit-IV- Pharma. Marketing Channels.pptxUnit-IV- Pharma. Marketing Channels.pptx
Unit-IV- Pharma. Marketing Channels.pptx
 
1029 - Danh muc Sach Giao Khoa 10 . pdf
1029 -  Danh muc Sach Giao Khoa 10 . pdf1029 -  Danh muc Sach Giao Khoa 10 . pdf
1029 - Danh muc Sach Giao Khoa 10 . pdf
 
TỔNG ÔN TẬP THI VÀO LỚP 10 MÔN TIẾNG ANH NĂM HỌC 2023 - 2024 CÓ ĐÁP ÁN (NGỮ Â...
TỔNG ÔN TẬP THI VÀO LỚP 10 MÔN TIẾNG ANH NĂM HỌC 2023 - 2024 CÓ ĐÁP ÁN (NGỮ Â...TỔNG ÔN TẬP THI VÀO LỚP 10 MÔN TIẾNG ANH NĂM HỌC 2023 - 2024 CÓ ĐÁP ÁN (NGỮ Â...
TỔNG ÔN TẬP THI VÀO LỚP 10 MÔN TIẾNG ANH NĂM HỌC 2023 - 2024 CÓ ĐÁP ÁN (NGỮ Â...
 
SOC 101 Demonstration of Learning Presentation
SOC 101 Demonstration of Learning PresentationSOC 101 Demonstration of Learning Presentation
SOC 101 Demonstration of Learning Presentation
 
Unit-IV; Professional Sales Representative (PSR).pptx
Unit-IV; Professional Sales Representative (PSR).pptxUnit-IV; Professional Sales Representative (PSR).pptx
Unit-IV; Professional Sales Representative (PSR).pptx
 

Stuff You Must Know Cold for the AP Calculus BC Exam!

  • 1. typed by Sean Bird, Covenant Christian High School updated August 15, 2009 AP CALCULUS Stuff you MUST know Cold * means topic only on BC Curve sketching and analysis Differentiation Rules Approx. Methods for Integration y = f(x) must be continuous at each: Chain Rule Trapezoidal Rule dy d du dy dy du b critical point: = 0 or undefined dx and look out for endpoints dx [ f (u )] = f '(u ) dx OR dx = du dx ∫a f ( x)dx = 1 b− a 2 n [ f ( x0 ) + 2 f ( x1 ) + ... local minimum: + 2 f ( xn −1 ) + f ( xn )] dy goes (–,0,+) or (–,und,+) or d 2 y >0 Product Rule Simpson’s Rule dx dx 2 b local maximum: d dx (uv) = du dx v+u dv dx OR u ' v + uv ' ∫a f ( x)dx = 2 1 dy goes (+,0,–) or (+,und,–) or d y <0 3 ∆x[ f ( x0 ) + 4 f ( x1 ) + 2 f ( x2 ) + ... dx dx 2 2 f ( xn −2 ) + 4 f ( xn−1 ) + f ( xn )] point of inflection: concavity changes Quotient Rule d 2 y goes from (+,0,–), (–,0,+), d u du dx v −u dv dx u ' v − uv '  = dx  v  v2 OR v2 dx 2 (+,und,–), or (–,und,+) Theorem of the Mean Value i.e. AVERAGE VALUE If the function f(x) is continuous on [a, b] Basic Derivatives “PLUS A CONSTANT” and the first derivative exists on the d n interval (a, b), then there exists a number dx ( ) x = nx n−1 The Fundamental Theorem of x = c on (a, b) such that Calculus b d ( sin x ) = cos x f (c ) = ∫ a f ( x)dx dx b (b − a) d ( cos x ) = − sin x ∫a f ( x)dx = F (b) − F (a) This value f(c) is the “average value” of dx where F '( x) = f ( x) the function on the interval [a, b]. d ( tan x ) = sec2 x dx Corollary to FTC Solids of Revolution and friends d ( cot x ) = − csc2 x Disk Method dx d b( x) x =b V =π∫ 2 [ R ( x)] dx ∫a ( x ) d f (t )dt = dx ( sec x ) = sec x tan x x=a dx Washer Method d f (b( x))b '( x) − f (a ( x))a '( x) dx ( csc x ) = − csc x cot x V =π∫ b a ([ R( x)] − [r ( x)] ) dx 2 2 Intermediate Value Theorem General volume equation (not rotated) d 1 du ( ln u ) = If the function f(x) is continuous on [a, b], b dx u dx and y is a number between f(a) and f(b), V = ∫ Area ( x) dx a d u du then there exists at least one number x= c dx ( ) e = eu dx in the open interval (a, b) such that *Arc Length L = ∫ 1 + [ f '( x)] dx b 2 a where u is a function of x, f (c ) = y . b =∫ 2 2 and a is a constant. a [ x '(t )] + [ y '(t )] dt More Derivatives Distance, Velocity, and Acceleration d  −1 u  1 du Mean Value Theorem velocity = d (position) sin = dx   a  2 a −u 2 dx dt If the function f(x) is continuous on [a, b], d (velocity) d −1 acceleration = AND the first derivative exists on the dx ( cos −1 x = ) interval (a, b), then there is at least one dt 1 − x2 dx dy number x = c in (a, b) such that *velocity vector = , d  −1 u  a du dt dt tan = ⋅ f (b) − f (a ) dx  a  a 2 + u 2 dx  f '(c) = . speed = v = ( x ')2 + ( y ') 2 * b−a d −1 dx ( cot −1 x = 1 + x2 ) displacement = ∫t tf v dt o d  −1 u  a du Rolle’s Theorem final time dx   sec = a  u u 2 − a 2 dx  ⋅ distance = ∫initial time v dt If the function f(x) is continuous on [a, b], tf d ( csc −1 x = −1 ) AND the first derivative exists on the ∫t o ( x ') 2 + ( y ') 2 dt * dx x x2 − 1 interval (a, b), AND f(a) = f(b), then there average velocity = is at least one number x = c in (a, b) such final position − initial position d u( x) du dx ( ) a = a ( ) ln a ⋅ u x dx that f '(c) = 0 . = total time ∆x d 1 = ( log a x ) = ∆t dx x ln a
  • 2. BC TOPICS and important TRIG identities and values l’Hôpital’s Rule Slope of a Parametric equation Values of Trigonometric f (a) 0 ∞ Given a x(t) and a y(t) the slope is Functions for Common Angles If = or = , g (b) 0 ∞ dy dy = dt θ sin θ cos θ tan θ f ( x) f '( x) dx dx then lim = lim dt x →a g ( x) x → a g '( x ) 0° 0 1 0 Euler’s Method Polar Curve π 1 3 3 If given that dy = f ( x, y ) and that For a polar curve r(θ), the 6 2 2 3 dx AREA inside a “leaf” is the solution passes through (xo, yo), θ2 2 π 2 2 y ( xo ) = yo ∫θ1 1 2  r (θ )  dθ   4 2 2 1 where θ1 and θ2 are the “first” two times that r = π 3 1 0. 3 y ( xn ) = y ( xn−1 ) + f ( xn−1 , yn−1 ) ⋅ ∆x 3 2 2 The SLOPE of r(θ) at a given θ is In other words: dy dy / dθ π = 1 0 “∞ ” xnew = xold + ∆x dx dx / dθ 2 dy π 0 −1 0 dθ  r (θ ) sin θ  d = d   ynew = yold + ⋅ ∆x Know both the inverse trig and the trig dx ( xold , yold ) dθ  r (θ ) cos θ    values. E.g. tan(π/4)=1 & tan-1(1)= π/4 Integration by Parts Ratio Test Trig Identities ∞ Double Argument ∫ udv = uv − ∫ vdu The series ∑ ak converges if k =0 sin 2 x = 2sin x cos x Integral of Log cos 2 x = cos 2 x − sin 2 x = 1 − 2sin 2 x Use IBP and let u = ln x (Recall ak +1 lim <1 1 u=LIPET) k →∞ ak cos 2 x = (1 + cos 2 x ) 2 ∫ ln x dx = x ln x − x + C If the limit equal 1, you know nothing. Taylor Series 1 If the function f is “smooth” at x = Lagrange Error Bound sin 2 x = (1 − cos 2 x ) 2 a, then it can be approximated by If Pn ( x) is the nth degree Taylor polynomial Pythagorean the nth degree polynomial of f(x) about c and f ( n+1) (t ) ≤ M for all t sin 2 x + cos 2 x = 1 f ( x) ≈ f (a ) + f '(a )( x − a) (others are easily derivable by between x and c, then + f ''(a) ( x − a)2 + … dividing by sin2x or cos2x) M n+1 2! f ( x) − Pn ( x) ≤ x−c 1 + tan 2 x = sec 2 x f ( n ) (a) ( n + 1)! + ( x − a)n . cot 2 x + 1 = csc 2 x n! Reciprocal Maclaurin Series 1 A Taylor Series about x = 0 is Alternating Series Error Bound sec x = or cos x sec x = 1 cos x called Maclaurin. 1 x 2 x3 N csc x = or sin x csc x = 1 If S N = ∑ ( −1) an is the Nth partial sum of a n ex = 1 + x + + +… sin x 2! 3! k =1 Odd-Even 2 x x4 convergent alternating series, then sin(–x) = – sin x (odd) cos x = 1 − + − … 2! 4! S∞ − S N ≤ aN +1 cos(–x) = cos x (even) x3 x5 Some more handy INTEGRALS: sin x = x − + − … 1 3! 5! Geometric Series ∞ ∫ tan x dx = ln sec x + C = 1 + x + x2 + x3 + … a + ar + ar 2 + ar 3 + … + ar n −1 + … = ∑ ar n −1 = − ln cos x + C 1− x n =1 x 2 x3 x 4 a ln( x + 1) = x − + − + … 2 3 4 diverges if |r|≥1; converges to 1− r if |r|<1 ∫ sec x dx = ln sec x + tan x + C This is available at http://covenantchristian.org/bird/Smart/Calc1/StuffMUSTknowColdNew.htm