3. Homologous series:
A homologous series is a group of organic
compounds having similar chemical
properties and a gradation of physical
properties..
They have a common generic formula.
Neighboring members differ by –CH2-
eg alkanes, alkenes, alkynes
10.1.1 Describe the features of a homologous series
5. Are these molecules part of a
homologous group?
Yes - They have a common
generic formula.
- Neighboring members differ
by –CH2-
6. Which statement about neighbouring
members of all homologous series is correct?
A. They have the same empirical formula.
B. They differ by a CH2 group.
C. They possess different functional groups.
D. They differ in their degree of unsaturation.
7. Which statement about neighbouring
members of all homologous series is correct?
A. They have the same empirical formula.
B. They differ by a CH2 group.
C. They possess different functional groups.
D. They differ in their degree of unsaturation.
8. Hydrocarbons
. . . compounds composed of carbon and
hydrogen.
Saturated: carbon-carbon bonds are all
single bonds - alkanes [CnH2n+2]
H C
H
H
C
H
H
H
Ethane
9.
10. The alkanes are a homologous series of saturated
hydrocarbons.
State the meaning of each of the following terms.
(i) homologous series
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(ii) hydrocarbon
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(iii) nomenclature
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11. Physical properties of Alkanes:
10.1.2 Predict and explain the trends in boiling points of members of a
homologous series
Alkanes Boiling
Point (O
C)
State
Methane CH4 -164
Gases
at RTEthane C2H6 -89
Propane C3H8 -42
Butane C4H10 -0.5
Pentane C5H12 36
Liquids
at RTHexane C6H14 69
Heptane C7H16 98
Octane C8H18 125
Boiling point increases with increasing
carbon numbers (increasing chain
length) due to increasing temporary
dipoles causing stronger van der
Waals’ forces between the molecules
as their size increases
Increase is not linear due to the
increase in chain length being
proportionally greater in smaller
molecules
Other physical properties that show
predictable trends with increasing chain
length are density and viscosity
12. Physical properties of Alkanes:
1. Name each compound
2. Use the idea of Van der Waals forces
to predict the comparative boiling
points and melting points of these
compounds.
A
D
CB
14. boiling point increases as number of carbons
increases
increased surface area / greater Van der Waals’
forces / increased Mr
increased intermolecular forces
Examiners report
generally done well, although boiling points were
sometimes explained in terms of an increase in the
number of bonds with no distinction between
intermolecular and intramolecular forces.
15. Which compound has the lowest boiling point?
A. CH3COOH
B. (CH3)4C
C. CH3CH2CH2CH2CH3
D. CH3CH2CH2CH2OH
16. Which compound has the lowest boiling point?
A. CH3COOH
B. (CH3)4C
C. CH3CH2CH2CH2CH3
D. CH3CH2CH2CH2OH
17. Empirical, molecular and structural
formula
Ethane
Empirical formula CH3
Molecular formula C2H6
Full structural formula
H H
H-C-C-H
H H
Condensed structural formula CH3CH3
10.1.3 Distinguish between empirical, molecular and structural formulas
18. Representing organic compounds.
An empirical formula gives the lowest whole number ratio of atoms
present in a compound eg: CH3
A molecular formula gives the actual number of atoms present in one
molecule of the substance eg: C2H6
A structural formula shows how the atoms are arranged in the
molecule.
1. A full structural formula displays every atom and bond eg:
2. A condensed structural formula omits bonds and can show identical
groups bracketed together eg:
CH3CH3 OR CH3(CH2)2CH3
( abbreviations such as R and can be used)
3. A skeleton formula for more complex structures can also be used.
( Do NOT use these in your exam answers) eg:
Would this represent C2H6 OR C4H10????
20. Which type of formula is used in each of the following:
CH2
C2H6
1. 2.
7.
4. 5. 6.
3.
21. Nomenclature:
Many organic compounds are known by a variety of names, and
many of these names give no indication of the nature of the
molecule.
e.g. for compounds from nature, the names may indicate the
source:
""-pinene" from pine trees or "citral" from citrus trees ...
These names are described as "Common" or "trivial" names (they
are not related to the chemical structure) – there are no rules
governing these names
A more systematic method was developed:
Unique name for each organic compound
Structure can be derived from name
RULES are used to derive these names
10.1.10 Apply IUPAC rules for naming compounds containing up to 6 carbon
atoms with one of the following functional groups: alcohol, aldehyde,
ketone, carboxylic acid and halide
22. Rules for Naming Alkanes(CnH2n+2)
1. For alkanes beyond butane, add -ane to
the Greek root for the number of carbons.
C-C-C-C-C-C = hexane
2. Alkyl substituents (ie groups joined onto
another group): drop the -ane and add -yl.
-C2H5 is ethyl
23. Rules for Naming Alkanes (cont)
3. Positions of substituent groups are
specified by numbering the longest chain
sequentially( from the end which produces
the smallest numbers!!).
C
|
C-C-C-C-C-C
3-methylhexane(not 4-methylhexane)
4. Location and name are followed by root
alkane name. Substituents are given in
alphabetical order with the use of di-, tri-, etc.
24. Given that the suffix –ol indicates the presence of an –OH group, draw
the structural diagram for the compound named above.
25. What is the IUPAC name for
CH3CH2CH(CH3)2?
(Hint: draw the structure first!!)
A. 1,1-dimethylpropane
B. 2-methylbutane
C. isopentane
D. ethyldimethylmethane
26. What is the IUPAC name for
CH3CH2CH(CH3)2?
(Hint: draw the structure first!!)
A. 1,1-dimethylpropane
B. 2-methylbutane
C. isopentane
D. ethyldimethylmethane
27. Which compound is a member of the same
homologous series as 1-chloropropane?
(remember – they must differ by –CH2- units)
A. 1-chloropropene
B. 1-chlorobutane
C. 1-bromopropane
D. 1,1-dichloropropane
28. Which compound is a member of the same
homologous series as 1-chloropropane?
(remember – they must differ by –CH2- units)
A. 1-chloropropene
B. 1-chlorobutane
C. 1-bromopropane
D. 1,1-dichloropropane
29. Which formula is a correct representation of
pentane?
A. CH3CH2CHCH2CH3
B. (CH3CH2)2CH3
C. CH3(CH2)3CH3
D. CH3(CH3)3CH3
30. Which formula is a correct representation of
pentane?
A. CH3CH2CHCH2CH3
B. (CH3CH2)2CH3
C. CH3(CH2)3CH3
D. CH3(CH3)3CH3
35. What are isomers?:
10.1.4 Describe structural isomers as compounds with the same molecular
formula but different arrangements of atoms
10.1.5 Deduce structural formulas for the isomers of the non-cyclic alkanes up
to C6
10.1.6 Apply IUPAC rules for naming the isomers of the non-cyclic alkanes up
to C6
10.1.7 Deduce structural formulas for the isomers of the straight chain
alkanes up to C6
10.1.8 Apply IUPAC rules for naming the isomers of the straight chain alkanes
up to C6
36. What are isomers?:
Isomers are compounds with the same
molecular formula but different arrangements
of atoms.
They will have the same molecular formula
but different structural formulae.
10.1.4 Describe structural isomers as compounds with the same molecular
formula but different arrangements of atoms
10.1.5 Deduce structural formulas for the isomers of the non-cyclic alkanes up
to C6
38. Which formulas represent butane or its isomer?
I. CH3(CH2)2CH3
II. CH3CH(CH3)CH3
III (CH3)3CH
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
39. Which formulas represent butane or its isomer?
I. CH3(CH2)2CH3
II. CH3CH(CH3)CH3
III (CH3)3CH
A. I and II only
B. I and III only
C. II and III only
D. I, II and III
40. They will have different IUPAC names.
Draw and name all of the isomers of C6H14
NB – remember all of the four bonds of a C atom are equivalent!
10.1.6 Apply IUPAC rules for naming the isomers of the non-cyclic alkanes up
to C6
41.
42. Cyclic Alkanes
Carbon atoms can form rings
containing only carbon-carbon single
bonds.
C3H6, C4H8, C6H12
Do cyclic alkanes have the same generic formula as straight
chain alkanes. Explain your answer.
43. Isomers of alkenes
A different type of structural isomer is formed
when the double bond is formed in different
positions
C4H8 has the following straight chain isomers
10.1.7 Deduce structural formulas for the isomers of the straight chain
alkenes up to C6
But-1-ene trans-but-2-ene cis-but-2-ene
44. 10.1.8 Apply IUPAC rules for
naming the isomers
of the straight chain
alkenes up to C6
Note – molecules are
named using the smallest
numbered carbon that is
part of the double bond
45. Volatility and Solubility
Structure of organic compounds can be
thought of in terms of:
1. a hydrocarbon skeleton
2. a functional group
Both influence the physical properties of an
organic compound, such as volatility and solubility
10.1.13 Discuss the volatility and solubility in water of compounds containing
the functional groups: alcohol, aldehyde, ketone, carboxylic acid and
halide
46. Volatility
Is a measure of how easily a substance
changes into the gaseous state
The higher the volatility the lower the BP.
(remember that BP / volatility depends on
over coming the forces between the
molecules – topic 4)
The stronger the intermolecular forces, the
higher the BP
47. Influence of the hydrocarbon skeleton
The larger the molecule the stronger the van der
Waals’ (intermolecular) forces between the
molecules
Increasing the number of carbons in the
hydrocarbon skeleton increases the BP /
decreases volatility
Lower members of a homologous series are
usually gases or liquids at RT. Higher members
are mostly solids
48. Influence of the hydrocarbon skeleton
Branching decreases the ability of the molecules
to align (line up next to each other) thus increases
the distance between the molecules and
decreases the intermolecular forces between
them
Increased branching, increases volatility /
decreases BP
Foe example
Butane BP = - 0.5 o
C
2-methylpropane BP = - 11.7o
C (branched isomer of
butane)
49. Influence of the functional group
In addition to van der Waals’ forces,
functional groups that are polar contribute to
intermolecular forces and thus increase BP /
decrease volatility
Polar groups develop dipole-dipole
interactions between molecules, which
increase BP
Groups that form hydrogen bonds form even
stronger intermolecular forces between
molecules
50. Summary - volatility
When comparing BP in different homologous
series, it’s important to compare molecules
with similar molecular masses. Which means
that the number of carbon is often different
For example
ethanol (C2H5OH), Mr = 46, BP = 78o
C
propane (C3H8), Mr = 44, BP = - 42o
C
Why does ethanol have a higher BP?
51. Summary - volatility
Most volatile least volatile
Alkane halogenoalkanes aldehyde ketone˃ ˃ ˃ ˃
alcohol carboxylic acid˃
Van der Waals’ dipole-dipole hydrogen bonding
Increasing strength of molecular attraction
Increasing boiling point
52. Solubility in water
Largely determined by the extent to which the
solute molecules can interact to form
hydrogen bonds with water
Influence of the hydrocarbon skeleton
Non-polar, therefore unable to form hydrogen
bonds and thus does not contribute to the
solubility of the molecule
Therefore, higher members of a homologous
series are less soluble that lower members
53. Solubility in water
Influence of the functional group
Molecules with functional groups that can form
hydrogen bonds with water are soluble.
Alcohol, carboxylic acid and amines are
soluble in water.
Aldehydes, ketones, amides and esters are
less soluble
halogenoalkanes., alkanes and alkenes are
insoluble